### 题目

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:
Each input file contains one test case. Each case occupies one line which contains an N (≤10​100).

Output Specification:
For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:
12345
Sample Output:
one five

### 代码

#include <iostream>
using namespace std;

int main() {
// int 无法存储
string strNum;
cin >> strNum;
int len = strNum.length();
int sum = 0;
// 每一位加起来
for (int i = 0; i < len; ++i) {
sum += (strNum[i] - '0');
}
// 结果转为字符串，每一位用英文表示
string strSum = to_string(sum);
// 映射表
string map[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
// 输出第一个位置
cout << map[strSum[0] - '0'];
// 输出 空格 其他位置，这样可以满足输出格式要求，最末尾不能有多余空格
len = strSum.length();
for (int i = 1; i < len; ++i) {
cout << " " << map[strSum[i] - '0'];
}
}